2c^2+9c-3=0

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Solution for 2c^2+9c-3=0 equation: 



2c^2+9c-3=0

a = 2; b = 9; c = -3;
Δ = b2-4ac
Δ = 92-4·2·(-3)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{105}}{2*2}=\frac{-9-\sqrt{105}}{4}
$


$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{105}}{2*2}=\frac{-9+\sqrt{105}}{4}
$

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